3.11.70 \(\int \sqrt {a+a x} \sqrt {c-c x} \, dx\)

Optimal. Leaf size=67 \[ \frac {1}{2} x \sqrt {a x+a} \sqrt {c-c x}+\sqrt {a} \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {c} \sqrt {a x+a}}{\sqrt {a} \sqrt {c-c x}}\right ) \]

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Rubi [A]  time = 0.03, antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {38, 63, 217, 203} \begin {gather*} \frac {1}{2} x \sqrt {a x+a} \sqrt {c-c x}+\sqrt {a} \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {c} \sqrt {a x+a}}{\sqrt {a} \sqrt {c-c x}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + a*x]*Sqrt[c - c*x],x]

[Out]

(x*Sqrt[a + a*x]*Sqrt[c - c*x])/2 + Sqrt[a]*Sqrt[c]*ArcTan[(Sqrt[c]*Sqrt[a + a*x])/(Sqrt[a]*Sqrt[c - c*x])]

Rule 38

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(x*(a + b*x)^m*(c + d*x)^m)/(2*m + 1)
, x] + Dist[(2*a*c*m)/(2*m + 1), Int[(a + b*x)^(m - 1)*(c + d*x)^(m - 1), x], x] /; FreeQ[{a, b, c, d}, x] &&
EqQ[b*c + a*d, 0] && IGtQ[m + 1/2, 0]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int \sqrt {a+a x} \sqrt {c-c x} \, dx &=\frac {1}{2} x \sqrt {a+a x} \sqrt {c-c x}+\frac {1}{2} (a c) \int \frac {1}{\sqrt {a+a x} \sqrt {c-c x}} \, dx\\ &=\frac {1}{2} x \sqrt {a+a x} \sqrt {c-c x}+c \operatorname {Subst}\left (\int \frac {1}{\sqrt {2 c-\frac {c x^2}{a}}} \, dx,x,\sqrt {a+a x}\right )\\ &=\frac {1}{2} x \sqrt {a+a x} \sqrt {c-c x}+c \operatorname {Subst}\left (\int \frac {1}{1+\frac {c x^2}{a}} \, dx,x,\frac {\sqrt {a+a x}}{\sqrt {c-c x}}\right )\\ &=\frac {1}{2} x \sqrt {a+a x} \sqrt {c-c x}+\sqrt {a} \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {c} \sqrt {a+a x}}{\sqrt {a} \sqrt {c-c x}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 69, normalized size = 1.03 \begin {gather*} \frac {\sqrt {a (x+1)} \left (x \sqrt {x+1} \sqrt {c-c x}-2 \sqrt {c} \sin ^{-1}\left (\frac {\sqrt {c-c x}}{\sqrt {2} \sqrt {c}}\right )\right )}{2 \sqrt {x+1}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a + a*x]*Sqrt[c - c*x],x]

[Out]

(Sqrt[a*(1 + x)]*(x*Sqrt[1 + x]*Sqrt[c - c*x] - 2*Sqrt[c]*ArcSin[Sqrt[c - c*x]/(Sqrt[2]*Sqrt[c])]))/(2*Sqrt[1
+ x])

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IntegrateAlgebraic [A]  time = 0.19, size = 105, normalized size = 1.57 \begin {gather*} -\frac {a c \sqrt {c-c x} \left (\frac {a (c-c x)}{a x+a}-c\right )}{\sqrt {a x+a} \left (\frac {a (c-c x)}{a x+a}+c\right )^2}-\sqrt {a} \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c-c x}}{\sqrt {c} \sqrt {a x+a}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[Sqrt[a + a*x]*Sqrt[c - c*x],x]

[Out]

-((a*c*Sqrt[c - c*x]*(-c + (a*(c - c*x))/(a + a*x)))/(Sqrt[a + a*x]*(c + (a*(c - c*x))/(a + a*x))^2)) - Sqrt[a
]*Sqrt[c]*ArcTan[(Sqrt[a]*Sqrt[c - c*x])/(Sqrt[c]*Sqrt[a + a*x])]

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fricas [A]  time = 1.60, size = 127, normalized size = 1.90 \begin {gather*} \left [\frac {1}{2} \, \sqrt {a x + a} \sqrt {-c x + c} x + \frac {1}{4} \, \sqrt {-a c} \log \left (2 \, a c x^{2} + 2 \, \sqrt {-a c} \sqrt {a x + a} \sqrt {-c x + c} x - a c\right ), \frac {1}{2} \, \sqrt {a x + a} \sqrt {-c x + c} x - \frac {1}{2} \, \sqrt {a c} \arctan \left (\frac {\sqrt {a c} \sqrt {a x + a} \sqrt {-c x + c} x}{a c x^{2} - a c}\right )\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+a)^(1/2)*(-c*x+c)^(1/2),x, algorithm="fricas")

[Out]

[1/2*sqrt(a*x + a)*sqrt(-c*x + c)*x + 1/4*sqrt(-a*c)*log(2*a*c*x^2 + 2*sqrt(-a*c)*sqrt(a*x + a)*sqrt(-c*x + c)
*x - a*c), 1/2*sqrt(a*x + a)*sqrt(-c*x + c)*x - 1/2*sqrt(a*c)*arctan(sqrt(a*c)*sqrt(a*x + a)*sqrt(-c*x + c)*x/
(a*c*x^2 - a*c))]

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giac [B]  time = 0.90, size = 173, normalized size = 2.58 \begin {gather*} -\frac {{\left (\frac {2 \, a^{2} c \log \left ({\left | -\sqrt {-a c} \sqrt {a x + a} + \sqrt {-{\left (a x + a\right )} a c + 2 \, a^{2} c} \right |}\right )}{\sqrt {-a c}} - \sqrt {-{\left (a x + a\right )} a c + 2 \, a^{2} c} \sqrt {a x + a}\right )} {\left | a \right |}}{a^{2}} + \frac {{\left (\frac {2 \, a^{3} c \log \left ({\left | -\sqrt {-a c} \sqrt {a x + a} + \sqrt {-{\left (a x + a\right )} a c + 2 \, a^{2} c} \right |}\right )}{\sqrt {-a c}} + \sqrt {-{\left (a x + a\right )} a c + 2 \, a^{2} c} \sqrt {a x + a} {\left (a x - 2 \, a\right )}\right )} {\left | a \right |}}{2 \, a^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+a)^(1/2)*(-c*x+c)^(1/2),x, algorithm="giac")

[Out]

-(2*a^2*c*log(abs(-sqrt(-a*c)*sqrt(a*x + a) + sqrt(-(a*x + a)*a*c + 2*a^2*c)))/sqrt(-a*c) - sqrt(-(a*x + a)*a*
c + 2*a^2*c)*sqrt(a*x + a))*abs(a)/a^2 + 1/2*(2*a^3*c*log(abs(-sqrt(-a*c)*sqrt(a*x + a) + sqrt(-(a*x + a)*a*c
+ 2*a^2*c)))/sqrt(-a*c) + sqrt(-(a*x + a)*a*c + 2*a^2*c)*sqrt(a*x + a)*(a*x - 2*a))*abs(a)/a^3

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maple [A]  time = 0.01, size = 98, normalized size = 1.46 \begin {gather*} \frac {\sqrt {\left (-c x +c \right ) \left (a x +a \right )}\, a c \arctan \left (\frac {\sqrt {a c}\, x}{\sqrt {-a c \,x^{2}+a c}}\right )}{2 \sqrt {-c x +c}\, \sqrt {a x +a}\, \sqrt {a c}}-\frac {\sqrt {a x +a}\, \left (-c x +c \right )^{\frac {3}{2}}}{2 c}+\frac {\sqrt {a x +a}\, \sqrt {-c x +c}}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+a)^(1/2)*(-c*x+c)^(1/2),x)

[Out]

-1/2/c*(a*x+a)^(1/2)*(-c*x+c)^(3/2)+1/2*(a*x+a)^(1/2)*(-c*x+c)^(1/2)+1/2*a*c*((-c*x+c)*(a*x+a))^(1/2)/(-c*x+c)
^(1/2)/(a*x+a)^(1/2)/(a*c)^(1/2)*arctan((a*c)^(1/2)/(-a*c*x^2+a*c)^(1/2)*x)

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maxima [A]  time = 3.08, size = 28, normalized size = 0.42 \begin {gather*} \frac {a c \arcsin \relax (x)}{2 \, \sqrt {a c}} + \frac {1}{2} \, \sqrt {-a c x^{2} + a c} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+a)^(1/2)*(-c*x+c)^(1/2),x, algorithm="maxima")

[Out]

1/2*a*c*arcsin(x)/sqrt(a*c) + 1/2*sqrt(-a*c*x^2 + a*c)*x

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mupad [B]  time = 0.30, size = 59, normalized size = 0.88 \begin {gather*} \frac {x\,\sqrt {a+a\,x}\,\sqrt {c-c\,x}}{2}-\frac {\sqrt {a}\,\sqrt {-c}\,\ln \left (\sqrt {-c}\,\sqrt {a\,\left (x+1\right )}\,\sqrt {-c\,\left (x-1\right )}-\sqrt {a}\,c\,x\right )}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + a*x)^(1/2)*(c - c*x)^(1/2),x)

[Out]

(x*(a + a*x)^(1/2)*(c - c*x)^(1/2))/2 - (a^(1/2)*(-c)^(1/2)*log((-c)^(1/2)*(a*(x + 1))^(1/2)*(-c*(x - 1))^(1/2
) - a^(1/2)*c*x))/2

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {a \left (x + 1\right )} \sqrt {- c \left (x - 1\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+a)**(1/2)*(-c*x+c)**(1/2),x)

[Out]

Integral(sqrt(a*(x + 1))*sqrt(-c*(x - 1)), x)

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